修复恢复时光标错误的问题 (fixed qinci#2)

Author: qinci

README.md

@@ -4,7 +4,7 @@
 ####EditText的撤销和恢复撤销操作
 #####使用
 * 引入库
-	* compile 'ren.qinc.edit:lib:0.0.3'
+	* compile 'ren.qinc.edit:lib:0.0.4'
 * 初始化
 
 ```java

gradle/push.gradle

@@ -1,7 +1,7 @@
 //参考http://www.jianshu.com/p/0ba8960f80a9
 apply plugin: 'com.github.dcendents.android-maven'
 apply plugin: 'com.jfrog.bintray'
-version = "0.0.3"
+version = "0.0.4"
 
 def siteUrl = 'https://github.com/qinci/AndroidEdit'   // 项目的主页
 def gitUrl = 'https://github.com/qinci/AndroidEdit.git'   // Git仓库的url

lib/build.gradle

@@ -6,8 +6,8 @@ android {
     defaultConfig {
         minSdkVersion 9
         targetSdkVersion 23
-        versionCode 2
-        versionName "1.2"
+        versionCode 3
+        versionName "1.3"
     }
     buildTypes {
         release {

lib/src/main/java/ren/qinc/edit/PerformEdit.java

@@ -84,7 +84,11 @@ public final void undo() {
         } else {
             //插销删除
             editable.insert(action.startCursor, action.actionTarget);
-            editText.setSelection(action.startCursor, action.endCursor);
+            if (action.endCursor == action.startCursor) {
+                editText.setSelection(action.startCursor + action.actionTarget.length());
+            } else {
+                editText.setSelection(action.startCursor, action.endCursor);
+            }
         }
         //释放操作
         flag = false;
@@ -151,7 +155,7 @@ public final void beforeTextChanged(CharSequence s, int start, int count, int af
                     if (count > 1) {
                         //如果一次超过一个字符，说名用户选择了，然后替换或者删除操作
                         action.setSelectCount(count);
-                    }else if(count==1&&count==after){
+                    } else if (count == 1 && count == after) {
                         //一个字符替换
                         action.setSelectCount(count);
                     }