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58. Length of Last Word
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markdown/58. Length of Last Word.md

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### [58\. Length of Last Word](https://leetcode.com/problems/length-of-last-word/)
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Difficulty: **Easy**
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Given a string _s_ consists of upper/lower-case alphabets and empty space characters `' '`, return the length of last word in the string.
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If the last word does not exist, return 0.
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**Note:** A word is defined as a character sequence consists of non-space characters only.
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**Example:**
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```
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Input: "Hello World"
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Output: 5
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```
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#### Solution
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Language: **Java**
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```java
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class Solution {
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   public int lengthOfLastWord(String s) {
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       if (s == null) {
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           return 0;
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      }
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       s = s.trim();
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       char[] chars = s.toCharArray();
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       int length = 0;
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       for (int i = chars.length - 1; i >= 0; i--) {
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           if (chars[i] != ' ') {
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               length++;
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          } else {
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               break;
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          }
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      }
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       return length;
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  }
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}
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```
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![](http://ww1.sinaimg.cn/large/006tNc79ly1g4xg3lcobsj31bk0s2gqt.jpg)

src/main/java/leetcode/_58_/Main.java

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package leetcode._58_;
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/**
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* Created by zhangbo54 on 2019-03-04.
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*/
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public class Main {
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public static void main(String[] args) {
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Solution solution = new Solution();
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System.out.println(solution.lengthOfLastWord("a"));
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}
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}
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package leetcode._58_;
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class Solution {
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public int lengthOfLastWord(String s) {
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if (s == null) {
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return 0;
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}
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s = s.trim();
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char[] chars = s.toCharArray();
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int length = 0;
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for (int i = chars.length - 1; i >= 0; i--) {
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if (chars[i] != ' ') {
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length++;
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} else {
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break;
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}
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}
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return length;
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}
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}
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### [58\. Length of Last Word](https://leetcode.com/problems/length-of-last-word/)
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Difficulty: **Easy**
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Given a string _s_ consists of upper/lower-case alphabets and empty space characters `' '`, return the length of last word in the string.
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If the last word does not exist, return 0.
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**Note:** A word is defined as a character sequence consists of non-space characters only.
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**Example:**
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```
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Input: "Hello World"
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Output: 5
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```
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#### Solution
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Language: **Java**
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```java
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class Solution {
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   public int lengthOfLastWord(String s) {
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       if (s == null) {
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           return 0;
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      }
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       s = s.trim();
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       char[] chars = s.toCharArray();
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       int length = 0;
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       for (int i = chars.length - 1; i >= 0; i--) {
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           if (chars[i] != ' ') {
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               length++;
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          } else {
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               break;
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          }
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      }
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       return length;
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  }
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}
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```
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![](http://ww1.sinaimg.cn/large/006tNc79ly1g4xg3lcobsj31bk0s2gqt.jpg)

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