58. Length of Last Word

Author: coderbean

markdown/58. Length of Last Word.md

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+### [58\. Length of Last Word](https://leetcode.com/problems/length-of-last-word/)
+
+Difficulty: **Easy**
+
+
+Given a string _s_ consists of upper/lower-case alphabets and empty space characters `' '`, return the length of last word in the string.
+
+If the last word does not exist, return 0.
+
+**Note:** A word is defined as a character sequence consists of non-space characters only.
+
+**Example:**
+
+```
+Input: "Hello World"
+Output: 5
+```
+
+
+#### Solution
+
+Language: **Java**
+
+```java
+class Solution {
+    public int lengthOfLastWord(String s) {
+        if (s == null) {
+            return 0;
+        }
+        s = s.trim();
+        char[] chars = s.toCharArray();
+        int length = 0;
+        for (int i = chars.length - 1; i >= 0; i--) {
+            if (chars[i] != ' ') {
+                length++;
+            } else {
+                break;
+            }
+        }
+        return length;
+    }
+}
+```
+![](http://ww1.sinaimg.cn/large/006tNc79ly1g4xg3lcobsj31bk0s2gqt.jpg)

src/main/java/leetcode/_58_/Main.java

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+package leetcode._58_;
+
+/**
+ * Created by zhangbo54 on 2019-03-04.
+ */
+public class Main {
+    public static void main(String[] args) {
+        Solution solution = new Solution();
+        System.out.println(solution.lengthOfLastWord("a"));
+    }
+}
+

src/main/java/leetcode/_58_/Solution.java

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+package leetcode._58_;
+
+class Solution {
+    public int lengthOfLastWord(String s) {
+        if (s == null) {
+            return 0;
+        }
+        s = s.trim();
+        char[] chars = s.toCharArray();
+        int length = 0;
+        for (int i = chars.length - 1; i >= 0; i--) {
+            if (chars[i] != ' ') {
+                length++;
+            } else {
+                break;
+            }
+        }
+        return length;
+    }
+}

src/main/java/leetcode/_58_/solution.md

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+### [58\. Length of Last Word](https://leetcode.com/problems/length-of-last-word/)
+
+Difficulty: **Easy**
+
+
+Given a string _s_ consists of upper/lower-case alphabets and empty space characters `' '`, return the length of last word in the string.
+
+If the last word does not exist, return 0.
+
+**Note:** A word is defined as a character sequence consists of non-space characters only.
+
+**Example:**
+
+```
+Input: "Hello World"
+Output: 5
+```
+
+
+#### Solution
+
+Language: **Java**
+
+```java
+class Solution {
+    public int lengthOfLastWord(String s) {
+        if (s == null) {
+            return 0;
+        }
+        s = s.trim();
+        char[] chars = s.toCharArray();
+        int length = 0;
+        for (int i = chars.length - 1; i >= 0; i--) {
+            if (chars[i] != ' ') {
+                length++;
+            } else {
+                break;
+            }
+        }
+        return length;
+    }
+}
+```
+![](http://ww1.sinaimg.cn/large/006tNc79ly1g4xg3lcobsj31bk0s2gqt.jpg)