|
| 1 | + // 想到了开头,没有想到细节。。。 |
| 2 | + |
| 3 | + class Solution { |
| 4 | + void bfs(int x,int y,vector<vector<char>> &board) |
| 5 | + { |
| 6 | + queue<int> q; |
| 7 | + visited(x,y,board,q); |
| 8 | + while(!q.empty()) |
| 9 | + { |
| 10 | + int pos = q.front(); |
| 11 | + q.pop(); |
| 12 | + int posX = pos / board[0].size(); |
| 13 | + int posY = pos % board[0].size(); |
| 14 | + visited(posX-1,posY,board,q); |
| 15 | + visited(posX + 1,posY,board,q); |
| 16 | + visited(posX,posY-1,board,q); |
| 17 | + visited(posX,posY + 1,board,q); |
| 18 | + |
| 19 | + } |
| 20 | + |
| 21 | + } |
| 22 | + |
| 23 | + void visited(int x, int y,vector<vector<char>> &board,queue<int>&q) |
| 24 | + { |
| 25 | + const int m = board.size(); |
| 26 | + const int n = board[0].size(); |
| 27 | + if(x < 0 || x >= m || y < 0 || y >= n || board[x][y] != 'O') |
| 28 | + return; |
| 29 | + board[x][y] = '#'; // 这个很聪明~ |
| 30 | + q.push(x * n + y); |
| 31 | + |
| 32 | + } |
| 33 | + |
| 34 | + public: |
| 35 | + void solve(vector<vector<char>> &board) { |
| 36 | + if(board.size() <= 0) return; |
| 37 | + int n = board.size(); |
| 38 | + |
| 39 | + int m = board[0].size(); |
| 40 | + // 上下左右 |
| 41 | + for(int i = 0;i < m;i++) |
| 42 | + { |
| 43 | + bfs(0,i,board); |
| 44 | + bfs(n-1,i,board); |
| 45 | + } |
| 46 | + for(int j = 1;j < n-1;j++) |
| 47 | + { |
| 48 | + bfs(j,0,board); |
| 49 | + bfs(j,m-1,board); |
| 50 | + } |
| 51 | + |
| 52 | + for( int i = 0;i < n;i++) |
| 53 | + for(int j = 0;j < m;j++) |
| 54 | + { |
| 55 | + if(board[i][j] == '#') |
| 56 | + board[i][j] = 'O'; |
| 57 | + else |
| 58 | + if(board[i][j] == 'O') |
| 59 | + board[i][j] = 'X'; |
| 60 | + } |
| 61 | + |
| 62 | + } |
| 63 | + }; |
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