refactor 1075

Author: fishercoder1534

database/_1075.sql

@@ -1,62 +1,3 @@
---1075. Project Employees I
---
---Table: Project
---
---+-------------+---------+
---| Column Name | Type    |
---+-------------+---------+
---| project_id  | int     |
---| employee_id | int     |
---+-------------+---------+
---(project_id, employee_id) is the primary key of this table.
---employee_id is a foreign key to Employee table.
---Table: Employee
---
---+------------------+---------+
---| Column Name      | Type    |
---+------------------+---------+
---| employee_id      | int     |
---| name             | varchar |
---| experience_years | int     |
---+------------------+---------+
---employee_id is the primary key of this table.
---
---
---Write an SQL query that reports the average experience years of all the employees for each project, rounded to 2 digits.
---
---The query result format is in the following example:
---
---Project table:
---+-------------+-------------+
---| project_id  | employee_id |
---+-------------+-------------+
---| 1           | 1           |
---| 1           | 2           |
---| 1           | 3           |
---| 2           | 1           |
---| 2           | 4           |
---+-------------+-------------+
---
---Employee table:
---+-------------+--------+------------------+
---| employee_id | name   | experience_years |
---+-------------+--------+------------------+
---| 1           | Khaled | 3                |
---| 2           | Ali    | 2                |
---| 3           | John   | 1                |
---| 4           | Doe    | 2                |
---+-------------+--------+------------------+
---
---Result table:
---+-------------+---------------+
---| project_id  | average_years |
---+-------------+---------------+
---| 1           | 2.00          |
---| 2           | 2.50          |
---+-------------+---------------+
---The average experience years for the first project is (3 + 2 + 1) / 3 = 2.00 and for the second project is (3 + 2) / 2 = 2.50
-
---# Write your MySQL query statement below
 select project_id, round(avg(experience_years), 2) as average_years
 from Project
 join Employee