add 1083

Author: fishercoder1534

README.md

@@ -852,6 +852,7 @@ _If you like this project, please leave me a star._ ★
 |1179|[Reformat Department Table](https://leetcode.com/problems/reformat-department-table/)|[Solution](../master/database/_1179.sql) |  | Easy |
 |1173|[Immediate Food Delivery I](https://leetcode.com/problems/immediate-food-delivery-i/)|[Solution](../master/database/_1173.sql) |  | Easy |
 |1148|[Article Views I](https://leetcode.com/problems/article-views-i/)|[Solution](../master/database/_1148.sql) |  | Easy |
+|1083|[Sales Analysis II](https://leetcode.com/problems/sales-analysis-ii/)|[Solution](../master/database/_1083.sql) |  | Easy |
 |1082|[Sales Analysis I](https://leetcode.com/problems/sales-analysis-i/)|[Solution](../master/database/_1082.sql) |  | Easy |
 |1069|[Product Sales Analysis II](https://leetcode.com/problems/product-sales-analysis-ii/)|[Solution](../master/database/_1069.sql) |  | Easy |
 |1068|[Product Sales Analysis I](https://leetcode.com/problems/product-sales-analysis-i/)|[Solution](../master/database/_1068.sql) | | Easy |

database/_1083.sql

@@ -0,0 +1,70 @@
+--1083. Sales Analysis II
+--
+--Table: Product
+--
+--+--------------+---------+
+--| Column Name  | Type    |
+--+--------------+---------+
+--| product_id   | int     |
+--| product_name | varchar |
+--| unit_price   | int     |
+--+--------------+---------+
+--product_id is the primary key of this table.
+--Table: Sales
+--
+--+-------------+---------+
+--| Column Name | Type    |
+--+-------------+---------+
+--| seller_id   | int     |
+--| product_id  | int     |
+--| buyer_id    | int     |
+--| sale_date   | date    |
+--| quantity    | int     |
+--| price       | int     |
+--+------ ------+---------+
+--This table has no primary key, it can have repeated rows.
+--product_id is a foreign key to Product table.
+--
+--
+--Write an SQL query that reports the buyers who have bought S8 but not iPhone. Note that S8 and iPhone are products present in the Product table.
+--
+--The query result format is in the following example:
+--
+--Product table:
+--+------------+--------------+------------+
+--| product_id | product_name | unit_price |
+--+------------+--------------+------------+
+--| 1          | S8           | 1000       |
+--| 2          | G4           | 800        |
+--| 3          | iPhone       | 1400       |
+--+------------+--------------+------------+
+--
+--Sales table:
+--+-----------+------------+----------+------------+----------+-------+
+--| seller_id | product_id | buyer_id | sale_date  | quantity | price |
+--+-----------+------------+----------+------------+----------+-------+
+--| 1         | 1          | 1        | 2019-01-21 | 2        | 2000  |
+--| 1         | 2          | 2        | 2019-02-17 | 1        | 800   |
+--| 2         | 1          | 3        | 2019-06-02 | 1        | 800   |
+--| 3         | 3          | 3        | 2019-05-13 | 2        | 2800  |
+--+-----------+------------+----------+------------+----------+-------+
+--
+--Result table:
+--+-------------+
+--| buyer_id    |
+--+-------------+
+--| 1           |
+--+-------------+
+--The buyer with id 1 bought an S8 but didn't buy an iPhone. The buyer with id 3 bought both.
+
+--# Write your MySQL query statement below
+select distinct buyer_id from Sales s
+join Product p
+on p.product_id = s.product_id
+where p.product_name = 'S8'
+and buyer_id not in
+(
+select buyer_id from Sales s
+    join Product p on p.product_id = s.product_id
+    where p.product_name = 'iPhone'
+)