modified: more-on-functions/studio/part-one-find-minimum-value.js

	modified:   more-on-functions/studio/part-three-number-sorting-easy-way.js
	modified:   more-on-functions/studio/part-two-create-sorted-array.js

Author: imrn16

more-on-functions/studio/part-one-find-minimum-value.js

@@ -1,10 +1,20 @@
 //1) Create a function with an array of numbers as its parameter. The function should iterate through the array and return the minimum value from the array. Hint: Use what you know about if statements to identify and store the smallest value within the array.
 
+function smallNum(arr) {
+	let prev = arr[0];
+	arr.map((indiv) => {
+		if (indiv < prev) {
+			prev = indiv;
+		}
+	});
+	return prev;
+}
+
 //Sample arrays for testing:
 let nums1 = [5, 10, 2, 42];
 let nums2 = [-2, 0, -10, -44, 5, 3, 0, 3];
 let nums3 = [200, 5, 4, 10, 8, 5, -3.3, 4.4, 0];
 
 //Using one of the test arrays as the argument, call your function inside the console.log statement below.
 
-console.log(/* your code here */);
+console.log(smallNum(nums1));

more-on-functions/studio/part-three-number-sorting-easy-way.js

@@ -5,4 +5,16 @@ let nums3 = [200, 5, 4, 10, 8, 5, -3.3, 4.4, 0];
 
 //Sort each array in ascending order.
 
+function ascend(arr) {
+	return arr.sort((a, b) => a - b);
+}
+
+console.log(ascend(nums3));
+
 //Sort each array in descending order.
+
+function descend(arr) {
+	return arr.sort((a, b) => b - a);
+}
+
+console.log(descend(nums3));

more-on-functions/studio/part-two-create-sorted-array.js

@@ -20,10 +20,27 @@ function findMinValue(arr){
 
 //Your function here...
 
+function newArr(arr) {
+  let arrTwo = []
+
+  while (arr.length > 0) {
+    let small = findMinValue(arr)
+    arrTwo.push(small)
+    arr.splice(arr.indexOf(small), 1)
+  } 
+  
+  return arrTwo
+
+}
+
 /* BONUS MISSION: Refactor your sorting function to use recursion below:
  */
 
 //Sample arrays for testing:
 let nums1 = [5, 10, 2, 42];
 let nums2 = [-2, 0, -10, -44, 5, 3, 0, 3];
 let nums3 = [200, 5, 4, 10, 8, 5, -3.3, 4.4, 0];
+
+
+
+console.log(newArr(nums3))