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‎.ipynb_checkpoints/Week3_Ligang_Zhang-checkpoint.ipynb

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{
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"cells": [
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"1. Write a Python function that takes a list of words and reytrns the length of the longest one"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 60,
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"metadata": {},
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"outputs": [
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{
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"data": {
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"text/plain": [
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"(8, 'resberry')"
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]
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},
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"execution_count": 60,
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"metadata": {},
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"output_type": "execute_result"
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}
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],
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"source": [
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"list1 = ['apple', 'banana', 'resberry', 'avacado']\n",
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"def get_longest_word(word_list):\n",
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" max_len = 0\n",
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" for word in word_list:\n",
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" if len(word) > max_len:\n",
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" max_len = len(word)\n",
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" result = word\n",
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" return max_len, result\n",
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"\n",
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"get_longest_word(list1)"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"2. Write a Python program to count the number of characters in a string"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 68,
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"metadata": {},
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"outputs": [
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{
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"data": {
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"text/plain": [
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"11"
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]
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},
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"execution_count": 68,
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"metadata": {},
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"output_type": "execute_result"
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}
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],
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"source": [
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"text = \"hello world\"\n",
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"def count_chars(txt):\n",
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" result = 0\n",
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" for char in txt:\n",
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" result += 1\n",
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" return result\n",
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"count_chars(text)"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 76,
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"metadata": {},
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"outputs": [
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{
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"data": {
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"text/plain": [
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"11"
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]
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},
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"execution_count": 76,
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"metadata": {},
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"output_type": "execute_result"
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}
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],
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"source": [
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"# second \n",
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"text = \"hello world\"\n",
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"def count_chars2(txt):\n",
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" return len(list(txt))\n",
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"count_chars2(text)"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"3. Write a Python program to sort (ascending and descending) a dictionary by value"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 2,
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"metadata": {},
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"outputs": [
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{
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"name": "stdout",
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"output_type": "stream",
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"text": [
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"{'a': 1, 'b': 100, 'c': 77, 'd': 66, 'e': 55}\n"
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]
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},
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{
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"data": {
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"text/plain": [
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"[('a', 1), ('e', 55), ('d', 66), ('c', 77), ('b', 100)]"
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]
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},
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"execution_count": 2,
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"metadata": {},
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"output_type": "execute_result"
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}
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],
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"source": [
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"dict1 = {'a':1, 'b':100, 'c':77, 'd':66, 'e':55}\n",
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"print(dict1)\n",
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"sorted(dict1.items(),key=lambda item:item[1])\n",
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"\n"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"4. Write a Python program to change a givern string to a new string where the first and last chars have been exchanged."
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]
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},
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{
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"cell_type": "code",
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"execution_count": 38,
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"metadata": {},
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"outputs": [
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{
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"name": "stdout",
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"output_type": "stream",
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"text": [
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"ABCello worlXYZ\n"
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]
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}
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],
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"source": [
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"text1 = 'hello world'\n",
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"list1 = list(text1)\n",
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"list1[0] = 'ABC'\n",
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"list1[-1] = 'XYZ'\n",
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"text2 = ''.join(list1)\n",
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"print(text2)"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"5. Write a Python function that takes two lists and returns True if they have at least one common member."
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]
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},
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{
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"cell_type": "code",
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"execution_count": 66,
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"metadata": {},
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"outputs": [
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{
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"name": "stdout",
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"output_type": "stream",
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"text": [
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"{'apple', 'banana'}\n",
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"true\n"
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]
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}
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],
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"source": [
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"list1 = ['apple', 'banana', 'resberry', 'avacado']\n",
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"list2 = ['apple', 'banana', 'strawberry', 'cherry']\n",
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"list3 = set(list1).intersection(set(list2))\n",
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"print(list3)\n",
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"if list3:\n",
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" print(\"true\")\n",
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"else:\n",
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" print(\"false\")\n",
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" "
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"6. Write a Python function that return the minimum number of coins ($0.01, $0.1, $0.25, $1) that make a given value."
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]
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},
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{
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"cell_type": "code",
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"execution_count": 57,
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"metadata": {},
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"outputs": [
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{
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"name": "stdout",
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"output_type": "stream",
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"text": [
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"[88, 3, 1, 3]\n",
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"{'$1': 88, '$0.25': 3, '$0.1': 1, '$0.01': 3}\n"
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]
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}
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],
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"source": [
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"def main():\n",
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" return_change = 88.88 # input value here\n",
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" coins_list = [1, 0.25, 0.1, 0.01]\n",
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" coin1 = int(return_change/coins_list[0])\n",
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" cent1 = round(return_change - coin1, 2)\n",
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" coin2 = int(cent1/coins_list[1])\n",
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" cent2 = round(cent1 - coin2*coins_list[1], 2)\n",
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" coin3 = int(cent2/coins_list[2])\n",
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" cent3 = round(cent2 - coin3*coins_list[2], 2)\n",
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" coin4 = int(cent3/coins_list[3])\n",
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" return_coins = [coin1, coin2, coin3, coin4]\n",
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" return_dict = {\"$1\": coin1, \"$0.25\": coin2, \"$0.1\": coin3, \"$0.01\":coin4}\n",
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" print(return_coins)\n",
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" print(return_dict)\n",
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"if __name__ == \"__main__\":\n",
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" main()"
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"metadata": {},
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"outputs": [],
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"source": []
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}
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],
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"metadata": {
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"kernelspec": {
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"display_name": "Python 3",
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"language": "python",
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"name": "python3"
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},
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"language_info": {
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"codemirror_mode": {
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"name": "ipython",
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"version": 3
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},
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"file_extension": ".py",
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"mimetype": "text/x-python",
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"name": "python",
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"nbconvert_exporter": "python",
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"pygments_lexer": "ipython3",
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"version": "3.7.4"
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}
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},
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"nbformat": 4,
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"nbformat_minor": 2
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}

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