Create Ex Oh

Author: ratracegrad

Ex Oh

@@ -0,0 +1,49 @@
+/***************************************************************************************
+*                                                                                      *
+*                  CODERBYTE BEGINNER CHALLENGE                                        *
+*                                                                                      *
+*  Ex Oh                                                                               *
+*  Using the JavaScript language, have the function ExOh(str) take the str parameter   *
+*  being passed and return the string true if there is an equal number of x's and o's, *
+*  otherwise return the string false. Only these two letters will be entered in the    *
+*  string, no punctuation or numbers. For example: if str is "xooxxxxooxo" then the    *
+*  output should return false because there are 6 x's and 5 o's.                       *
+*                                                                                      *
+*  SOLUTION                                                                            *
+*  My solution accounts for the one outlier which is when the length of the string     *
+*  is not even. Since the count of Xs and Os have to be equal then the only way for    *
+*  this to happen is if the length of the string is an even number. I am going to      *
+*  loop through the string and count every X. Then I am going to compare this count    *
+*  to half the length of the string. If they are equal then you have equal number of   *
+*  Xs and Os.                                                                          *
+*                                                                                      *
+*  Steps for solution                                                                  *
+*    1) Handle outlier first by seeing if str length is odd                            *
+*    2) Loop thru each letter and count the number of Xs                               *
+*    3) Compare count to 1/2 length of str and if same then return true                *
+*    4) Else return false                                                              * 
+*                                                                                      *
+***************************************************************************************/
+function ExOh(str) { 
+
+  if (str.length % 2 === 1) {
+    return false;
+  } 
+  else {  
+    var tot = 0;
+    for (var i = 0; i < str.length; i++) {
+      if (str[i] === "x") {
+        tot++;
+      }
+    }
+    
+    if (tot === (str.length / 2)) {
+      return true;
+    }
+    else {
+      return false;
+    }
+
+  }
+         
+}