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Java - RandomAccessFile writeByte(int v) method
Description
The Java RandomAccessFile writeByte(int v) method writes a byte to the file as a one-byte value. The write starts at the current position of the file pointer.
Declaration
Following is the declaration for java.io.RandomAccessFile.writeByte(int v) method.
public final void writeByte(int v)
Parameters
v − The byte to be written.
Return Value
This method does not return a value.
Exception
IOException − If an I/O error occurs.
Example - Usage of RandomAccessFile writeByte(int v) method
The following example shows the usage of RandomAccessFile writeByte(int v) method.
RandomAccessFileDemo.java
package com.tutorialspoint;
import java.io.RandomAccessFile;
import java.io.IOException;
public class RandomAccessFileDemo {
public static void main(String[] args) {
try {
byte[] b1 = {15, 8};
// create a new RandomAccessFile with filename test
RandomAccessFile raf = new RandomAccessFile("test.txt", "rw");
// write something in the file
raf.writeByte(b1[0]);
// set the file pointer at 0 position
raf.seek(0);
// read byte
System.out.println(raf.readByte());
// set the file pointer at 0 position
raf.seek(0);
// write 0 at the start
raf.writeByte(b1[1]);
// set the file pointer at 0 position
raf.seek(0);
// read byte
System.out.println(raf.readByte());
} catch (IOException ex) {
ex.printStackTrace();
}
}
}
Output
Assuming we have a text file test.txt in current directory which has the following content. This file will be used as an input for our example program −
ABCDE
Let us compile and run the above program, this will produce the following result −
15 8
Example - Writing a Single Byte to a File
The following example shows the usage of RandomAccessFile writeByte(int v) method.
RandomAccessFileDemo.java
package com.tutorialspoint;
import java.io.RandomAccessFile;
import java.io.IOException;
public class RandomAccessFileDemo {
public static void main(String[] args) {
try {
RandomAccessFile raf = new RandomAccessFile("example1.dat", "rw");
raf.writeByte(65); // ASCII value of 'A'
raf.close();
System.out.println("Byte written to file.");
} catch (IOException e) {
e.printStackTrace();
}
}
}
Output
Let us compile and run the above program, this will produce the following result−
Byte written to file.
Explanation
This code opens (or creates) a file named example1.dat in read-write (rw) mode.
It writes the byte 65, which is the ASCII code for 'A'.
writeByte(int b) writes only the lowest 8 bits of the provided integer. So even though 65 is an int, only the byte value is used.
After writing, the file contains one byte: 'A'.
Example - Overwriting a Byte at a Specific Position
The following example shows the usage of RandomAccessFile writeByte(int v) method.
RandomAccessFileDemo.java
package com.tutorialspoint;
import java.io.RandomAccessFile;
import java.io.IOException;
public class RandomAccessFileDemo {
public static void main(String[] args) {
try {
RandomAccessFile raf = new RandomAccessFile("example2.dat", "rw");
// Write three bytes: A, B, C
raf.writeByte(65); // 'A'
raf.writeByte(66); // 'B'
raf.writeByte(67); // 'C'
// Move the file pointer to the second byte (position 1)
raf.seek(1);
// Overwrite the second byte with 'Z' (ASCII 90)
raf.writeByte(90);
raf.close();
System.out.println("Byte overwritten in file.");
} catch (IOException e) {
e.printStackTrace();
}
}
}
Output
Let us compile and run the above program, this will produce the following result−
Byte overwritten in file.
Explanation
First, this writes three bytes: 'A', 'B', and 'C' to example2.dat.
Then seek(1) moves the file pointer to the second byte (0-based index).
writeByte(90) overwrites 'B' with 'Z'.
Final file content is: 'A', 'Z', 'C'.