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Java - RandomAccessFile writeInt(int v) method
Description
The Java RandomAccessFile writeInt(int v) method writes an int to the file as four bytes, high byte first. The write starts at the current position of the file pointer.
writeInt(int v) method −
Writes the 4 bytes of the int value to the file.
The bytes are written in big-endian order (most significant byte first).
The file pointer advances by 4 bytes.
You can later read the value using readInt().
Declaration
Following is the declaration for java.io.RandomAccessFile.writeInt(int v) method.
public final void writeInt(int v)
Parameters
v − a int value to be written.
Return Value
This method does not return a value.
Exception
IOException − If an I/O error occurs.
Example - Usage of RandomAccessFile writeInt(int v) method
The following example shows the usage of RandomAccessFile writeInt(int v) method.
RandomAccessFileDemo.java
package com.tutorialspoint;
import java.io.RandomAccessFile;
import java.io.IOException;
public class RandomAccessFileDemo {
public static void main(String[] args) {
try {
int f = 1847;
// create a new RandomAccessFile with filename test
RandomAccessFile raf = new RandomAccessFile("test.txt", "rw");
// write an int in the file
raf.writeInt(f);
// set the file pointer at 0 position
raf.seek(0);
// read int
System.out.println(raf.readInt());
// set the file pointer at 0 position
raf.seek(0);
// write a int at the start
raf.writeInt(200);
// set the file pointer at 0 position
raf.seek(0);
// read int
System.out.println(raf.readInt());
} catch (IOException ex) {
ex.printStackTrace();
}
}
}
Output
Assuming we have a text file test.txt in current directory which has the following content. This file will be used as an input for our example program −
ABCDE
Let us compile and run the above program, this will produce the following result −
1847 200
Example - Write and Read a Single Integer
The following example shows the usage of RandomAccessFile writeInt(int v) method.
RandomAccessFileDemo.java
package com.tutorialspoint;
import java.io.RandomAccessFile;
import java.io.IOException;
public class RandomAccessFileDemo {
public static void main(String[] args) {
try (RandomAccessFile raf = new RandomAccessFile("int1.dat", "rw")) {
// Write an integer
raf.writeInt(2025);
// Move file pointer to start
raf.seek(0);
// Read the integer back
int value = raf.readInt();
System.out.println("Read int: " + value);
} catch (IOException e) {
e.printStackTrace();
}
}
}
Output
Let us compile and run the above program, this will produce the following result−
Read int: 2025
Explanation
2025 is stored as 4 bytes (big-endian).
File content (in hex): 00 00 07 E9 (2025 in hex is 0x07E9).
readInt() retrieves the same value.
Example - Write Multiple Integers and Read Them
The following example shows the usage of RandomAccessFile writeInt(int v) method.
RandomAccessFileDemo.java
package com.tutorialspoint;
import java.io.RandomAccessFile;
import java.io.IOException;
public class RandomAccessFileDemo {
public static void main(String[] args) {
try (RandomAccessFile raf = new RandomAccessFile("int2.dat", "rw")) {
// Write multiple integers
raf.writeInt(10);
raf.writeInt(20);
raf.writeInt(30);
// Move pointer to beginning
raf.seek(0);
// Read back the integers
int a = raf.readInt();
int b = raf.readInt();
int c = raf.readInt();
System.out.println("Read integers: " + a + ", " + b + ", " + c);
} catch (IOException e) {
e.printStackTrace();
}
}
}
Output
Let us compile and run the above program, this will produce the following result−
Read integers: 10, 20, 30
Explanation
Three integers (10, 20, 30) are written → 12 bytes total.
Each int occupies 4 bytes.
seek(0) resets the pointer to read from the start.