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 | 1 | +package com.thealgorithms.graph;  | 
 | 2 | + | 
 | 3 | +import java.util.Collections;  | 
 | 4 | +import java.util.HashMap;  | 
 | 5 | +import java.util.HashSet;  | 
 | 6 | +import java.util.LinkedList;  | 
 | 7 | +import java.util.List;  | 
 | 8 | +import java.util.Map;  | 
 | 9 | +import java.util.Set;  | 
 | 10 | +import java.util.Stack;  | 
 | 11 | + | 
 | 12 | +/**  | 
 | 13 | + * Implementation of Hierholzer's algorithm to find an Eulerian Circuit in an undirected graph.  | 
 | 14 | + * <p>  | 
 | 15 | + * An Eulerian circuit is a trail in a graph that visits every edge exactly once,  | 
 | 16 | + * starting and ending at the same vertex. This algorithm finds such a circuit if one exists.  | 
 | 17 | + * </p>  | 
 | 18 | + * <p>  | 
 | 19 | + * This implementation is designed for an <strong>undirected graph</strong>. For a valid Eulerian  | 
 | 20 | + * circuit to exist, the graph must satisfy two conditions:  | 
 | 21 | + * <ol>  | 
 | 22 | + * <li>All vertices with a non-zero degree must be part of a single connected component.</li>  | 
 | 23 | + * <li>Every vertex must have an even degree (an even number of edges connected to it).</li>  | 
 | 24 | + * </ol>  | 
 | 25 | + * </p>  | 
 | 26 | + * <p>  | 
 | 27 | + * The algorithm runs in O(E + V) time, where E is the number of edges and V is the number of vertices.  | 
 | 28 | + * The graph is represented by a Map where keys are vertices and values are a LinkedList of adjacent vertices.  | 
 | 29 | + * </p>  | 
 | 30 | + *  | 
 | 31 | + * @see <a href="https://en.wikipedia.org/wiki/Eulerian_path#Hierholzer's_algorithm">Wikipedia: Hierholzer's algorithm</a>  | 
 | 32 | + */  | 
 | 33 | +public final class HierholzerAlgorithm {  | 
 | 34 | + | 
 | 35 | +    private final Map<Integer, LinkedList<Integer>> graph;  | 
 | 36 | + | 
 | 37 | +    public HierholzerAlgorithm(Map<Integer, LinkedList<Integer>> graph) {  | 
 | 38 | +        this.graph = (graph == null) ? new HashMap<>() : graph;  | 
 | 39 | +    }  | 
 | 40 | + | 
 | 41 | +    public boolean hasEulerianCircuit() {  | 
 | 42 | +        if (graph.isEmpty()) {  | 
 | 43 | +            return true;  | 
 | 44 | +        }  | 
 | 45 | + | 
 | 46 | +        for (List<Integer> neighbors : graph.values()) {  | 
 | 47 | +            if (neighbors.size() % 2 != 0) {  | 
 | 48 | +                return false;  | 
 | 49 | +            }  | 
 | 50 | +        }  | 
 | 51 | + | 
 | 52 | +        return isCoherentlyConnected();  | 
 | 53 | +    }  | 
 | 54 | + | 
 | 55 | +    public List<Integer> findEulerianCircuit() {  | 
 | 56 | +        if (!hasEulerianCircuit()) {  | 
 | 57 | +            return Collections.emptyList();  | 
 | 58 | +        }  | 
 | 59 | + | 
 | 60 | +        Map<Integer, LinkedList<Integer>> tempGraph = new HashMap<>();  | 
 | 61 | +        for (Map.Entry<Integer, LinkedList<Integer>> entry : graph.entrySet()) {  | 
 | 62 | +            tempGraph.put(entry.getKey(), new LinkedList<>(entry.getValue()));  | 
 | 63 | +        }  | 
 | 64 | + | 
 | 65 | +        Stack<Integer> currentPath = new Stack<>();  | 
 | 66 | +        LinkedList<Integer> circuit = new LinkedList<>();  | 
 | 67 | + | 
 | 68 | +        int startVertex = -1;  | 
 | 69 | +        for (Map.Entry<Integer, LinkedList<Integer>> entry : tempGraph.entrySet()) {  | 
 | 70 | +            if (!entry.getValue().isEmpty()) {  | 
 | 71 | +                startVertex = entry.getKey();  | 
 | 72 | +                break;  | 
 | 73 | +            }  | 
 | 74 | +        }  | 
 | 75 | + | 
 | 76 | +        if (startVertex == -1) {  | 
 | 77 | +            if (graph.isEmpty()) {  | 
 | 78 | +                return Collections.emptyList();  | 
 | 79 | +            }  | 
 | 80 | +            return Collections.singletonList(graph.keySet().iterator().next());  | 
 | 81 | +        }  | 
 | 82 | + | 
 | 83 | +        currentPath.push(startVertex);  | 
 | 84 | + | 
 | 85 | +        while (!currentPath.isEmpty()) {  | 
 | 86 | +            int currentVertex = currentPath.peek();  | 
 | 87 | + | 
 | 88 | +            if (tempGraph.containsKey(currentVertex) && !tempGraph.get(currentVertex).isEmpty()) {  | 
 | 89 | +                int nextVertex = tempGraph.get(currentVertex).pollFirst();  | 
 | 90 | +                tempGraph.get(nextVertex).remove(Integer.valueOf(currentVertex));  | 
 | 91 | +                currentPath.push(nextVertex);  | 
 | 92 | +            } else {  | 
 | 93 | +                circuit.addFirst(currentVertex);  | 
 | 94 | +                currentPath.pop();  | 
 | 95 | +            }  | 
 | 96 | +        }  | 
 | 97 | + | 
 | 98 | +        return circuit;  | 
 | 99 | +    }  | 
 | 100 | + | 
 | 101 | +    private boolean isCoherentlyConnected() {  | 
 | 102 | +        if (graph.isEmpty()) {  | 
 | 103 | +            return true;  | 
 | 104 | +        }  | 
 | 105 | + | 
 | 106 | +        Set<Integer> visited = new HashSet<>();  | 
 | 107 | +        int startNode = -1;  | 
 | 108 | + | 
 | 109 | +        for (Map.Entry<Integer, LinkedList<Integer>> entry : graph.entrySet()) {  | 
 | 110 | +            if (!entry.getValue().isEmpty()) {  | 
 | 111 | +                startNode = entry.getKey();  | 
 | 112 | +                break;  | 
 | 113 | +            }  | 
 | 114 | +        }  | 
 | 115 | + | 
 | 116 | +        if (startNode == -1) {  | 
 | 117 | +            return true;  | 
 | 118 | +        }  | 
 | 119 | + | 
 | 120 | +        dfs(startNode, visited);  | 
 | 121 | + | 
 | 122 | +        for (Map.Entry<Integer, LinkedList<Integer>> entry : graph.entrySet()) {  | 
 | 123 | +            if (!entry.getValue().isEmpty() && !visited.contains(entry.getKey())) {  | 
 | 124 | +                return false;  | 
 | 125 | +            }  | 
 | 126 | +        }  | 
 | 127 | +        return true;  | 
 | 128 | +    }  | 
 | 129 | + | 
 | 130 | +    private void dfs(int u, Set<Integer> visited) {  | 
 | 131 | +        visited.add(u);  | 
 | 132 | +        if (graph.containsKey(u)) {  | 
 | 133 | +            for (int v : graph.get(u)) {  | 
 | 134 | +                if (!visited.contains(v)) {  | 
 | 135 | +                    dfs(v, visited);  | 
 | 136 | +                }  | 
 | 137 | +            }  | 
 | 138 | +        }  | 
 | 139 | +    }  | 
 | 140 | +}  | 
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