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Author: assassint2017

Palindrome Number/Palindrome_Number.py

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+# 第一种思路，将数字转换为字符串 
+# 252ms 99.32%
+class Solution:
+    def isPalindrome(self, x):
+        """
+        :type x: int
+        :rtype: bool
+        """
+        strs = str(x)
+        return True if strs == strs[::-1] else False
+
+# 第二种思路，把数字翻转过来判断两者是否相等
+# 268ms 90.11%
+class Solution:
+    def isPalindrome(self, x):
+        """
+        :type x: int
+        :rtype: bool
+        """
+        if x < 0:
+            return False
+        reverse, temp_x = 0, x
+        while x >= 10:
+            reverse = reverse * 10 + x % 10
+            x //= 10
+        reverse = reverse * 10 + x
+        return True if reverse == temp_x else False
+    
+# 第三种思路，不必翻转所有的数据，只需要翻转一半就可以了
+# 260ms 97.20%
+class Solution:
+    def isPalindrome(self, x):
+        """
+        :type x: int
+        :rtype: bool
+        """
+        if x < 0 or (x % 10 is 0 and x is not 0):
+            return False
+        reverse = 0
+        while x > reverse:
+            reverse = reverse * 10 + x % 10
+            x //= 10
+        return True if reverse == x or reverse // 10 == x else False