|  | 
|  | 1 | +class Node: | 
|  | 2 | +    """ | 
|  | 3 | +    A Node has data variable and pointers to its left and right nodes. | 
|  | 4 | +    """ | 
|  | 5 | + | 
|  | 6 | +    def __init__(self, data): | 
|  | 7 | +        self.left = None | 
|  | 8 | +        self.right = None | 
|  | 9 | +        self.data = data | 
|  | 10 | + | 
|  | 11 | +def make_tree() -> Node: | 
|  | 12 | +    root = Node(1) | 
|  | 13 | +    root.left = Node(2) | 
|  | 14 | +    root.right = Node(3) | 
|  | 15 | +    root.left.left = Node(4) | 
|  | 16 | +    root.left.right = Node(5) | 
|  | 17 | +    return root | 
|  | 18 | + | 
|  | 19 | +def zigzag_iterative(root: Node): | 
|  | 20 | +    """ | 
|  | 21 | +    ZigZag traverse by iterative method: Print node left to right and right to left, alternatively. | 
|  | 22 | +    """ | 
|  | 23 | +    if root == None:  | 
|  | 24 | +        return  | 
|  | 25 | +   | 
|  | 26 | +    # two stacks to store alternate levels   | 
|  | 27 | +    s1 = [] # For levels to be printed from right to left   | 
|  | 28 | +    s2 = [] # For levels to be printed from left to right   | 
|  | 29 | +   | 
|  | 30 | +    # append first level to first stack 's1'   | 
|  | 31 | +    s1.append(root)   | 
|  | 32 | +   | 
|  | 33 | +    # Keep printing while any of the stacks has some nodes   | 
|  | 34 | +    while not len(s1) == 0 or not len(s2) == 0:  | 
|  | 35 | +           | 
|  | 36 | +        # Print nodes of current level from s1 and append nodes of next level to s2   | 
|  | 37 | +        while not len(s1) == 0:  | 
|  | 38 | +            temp = s1[-1]   | 
|  | 39 | +            s1.pop()   | 
|  | 40 | +            print(temp.data, end = " ")   | 
|  | 41 | +   | 
|  | 42 | +            # Note that is left is appended before right     | 
|  | 43 | +            if temp.left:  | 
|  | 44 | +                s2.append(temp.left) | 
|  | 45 | +            if temp.right:   | 
|  | 46 | +                s2.append(temp.right) | 
|  | 47 | +   | 
|  | 48 | +        # Print nodes of current level from s2 and append nodes of next level to s1   | 
|  | 49 | +        while not len(s2) == 0:  | 
|  | 50 | +            temp = s2[-1]   | 
|  | 51 | +            s2.pop()   | 
|  | 52 | +            print(temp.data, end = " ")   | 
|  | 53 | +   | 
|  | 54 | +            # Note that is rightt is appended before left    | 
|  | 55 | +            if temp.right:   | 
|  | 56 | +                s1.append(temp.right) | 
|  | 57 | +            if temp.left:  | 
|  | 58 | +                s1.append(temp.left)   | 
|  | 59 | + | 
|  | 60 | +def main():  # Main function for testing. | 
|  | 61 | +    """ | 
|  | 62 | +    Create binary tree. | 
|  | 63 | +    """ | 
|  | 64 | +    root = make_tree() | 
|  | 65 | +    print("\nZigzag order traversal(iterative) is: ") | 
|  | 66 | +    zigzag_iterative(root) | 
|  | 67 | +    print() | 
|  | 68 | + | 
|  | 69 | + | 
|  | 70 | +if __name__ == "__main__": | 
|  | 71 | +    import doctest | 
|  | 72 | + | 
|  | 73 | +    doctest.testmod() | 
|  | 74 | +    main() | 
|  | 75 | +     | 
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