AMSTRONG NUMBER
import java.util.Scanner;
import java.lang.Math;
public class ArmstsrongNumberExample
{
//function to check if the number is Armstrong or not
static boolean isArmstrong(int n)
{
int temp, digits=0, last=0, sum=0;
//assigning n into a temp variable
temp=n;
//loop execute until the condition becomes false
while(temp>0)
{
temp = temp/10;
digits++;
}
temp = n;
while(temp>0)
{
//determines the last digit from the number
last = temp % 10;
//calculates the power of a number up to digit times and add the resultant to the sum variable
sum += (Math.pow(last, digits));
//removes the last digit
temp = temp/10;
}
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//compares the sum with n
if(n==sum)
//returns if sum and n are equal
return true;
//returns false if sum and n are not equal
else return false;
}
//driver code
public static void main(String args[])
{
int num;
Scanner sc= new Scanner(System.in);
System.out.print(“Enter the limit: “);
//reads the limit from the user
num=sc.nextInt();
System.out.println(“Armstrong Number up to “+ num + “ are: “);
for(int i=0; i<=num; i++)
//function calling
if(isArmstrong(i))
//prints the armstrong numbers
System.out.print(i+ “, “);
}
}
//OUTPUT:
Enter the limit: 999
Armstrong Number up to 999 are:
0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 153, 370, 371, 407
