Given Adjacency List representation of graph of N vertices from 1 to N, the task is to count the minimum bipartite groups of the given graph.
Examples:
Input: N = 5
Below is the given graph with number of nodes is 5:
![]()
Output: 3
Explanation:
Possible groups satisfying the Bipartite property: [2, 5], [1, 3], [4]
Below is the number of bipartite groups can be formed:
Approach:
The idea is to find the maximum height of all the Connected Components in the given graph of N nodes to find the minimum bipartite groups. Below are the steps:
- For all the non-visited vertex in the given graph, find the height of the current Connected Components starting from the current vertex.
- Start DFS Traversal to find the height of all the Connected Components.
- The maximum of the heights calculated for all the Connected Components gives the minimum bipartite groups required.
Below is the implementation of the above approach:
#include <bits/stdc++.h>
using namespace std;
// Function to find the height sizeof
// the current component with vertex s
int height(int s, vector<int> adj[],
int* visited)
{
// Visit the current Node
visited[s] = 1;
int h = 0;
// Call DFS recursively to find the
// maximum height of current CC
for (auto& child : adj[s]) {
// If the node is not visited
// then the height recursively
// for next element
if (visited[child] == 0) {
h = max(h, 1 + height(child, adj,
visited));
}
}
return h;
}
// Function to find the minimum Groups
int minimumGroups(vector<int> adj[], int N)
{
// Initialise with visited array
int visited[N + 1] = { 0 };
// To find the minimum groups
int groups = INT_MIN;
// Traverse all the non visited Node
// and calculate the height of the
// tree with current node as a head
for (int i = 1; i <= N; i++) {
// If the current is not visited
// therefore, we get another CC
if (visited[i] == 0) {
int comHeight;
comHeight = height(i, adj, visited);
groups = max(groups, comHeight);
}
}
// Return the minimum bipartite matching
return groups;
}
// Function that adds the current edges
// in the given graph
void addEdge(vector<int> adj[], int u, int v)
{
adj[u].push_back(v);
adj[v].push_back(u);
}
// Drivers Code
int main()
{
int N = 5;
// Adjacency List
vector<int> adj[N + 1];
// Adding edges to List
addEdge(adj, 1, 2);
addEdge(adj, 3, 2);
addEdge(adj, 4, 3);
cout << minimumGroups(adj, N);
}
import java.util.*;
class GFG{
// Function to find the height sizeof
// the current component with vertex s
static int height(int s, Vector<Integer> adj[],
int []visited)
{
// Visit the current Node
visited[s] = 1;
int h = 0;
// Call DFS recursively to find the
// maximum height of current CC
for (int child : adj[s]) {
// If the node is not visited
// then the height recursively
// for next element
if (visited[child] == 0) {
h = Math.max(h, 1 + height(child, adj,
visited));
}
}
return h;
}
// Function to find the minimum Groups
static int minimumGroups(Vector<Integer> adj[], int N)
{
// Initialise with visited array
int []visited= new int[N + 1];
// To find the minimum groups
int groups = Integer.MIN_VALUE;
// Traverse all the non visited Node
// and calculate the height of the
// tree with current node as a head
for (int i = 1; i <= N; i++) {
// If the current is not visited
// therefore, we get another CC
if (visited[i] == 0) {
int comHeight;
comHeight = height(i, adj, visited);
groups = Math.max(groups, comHeight);
}
}
// Return the minimum bipartite matching
return groups;
}
// Function that adds the current edges
// in the given graph
static void addEdge(Vector<Integer> adj[], int u, int v)
{
adj[u].add(v);
adj[v].add(u);
}
// Drivers Code
public static void main(String[] args)
{
int N = 5;
// Adjacency List
Vector<Integer> []adj = new Vector[N + 1];
for (int i = 0 ; i < N + 1; i++)
adj[i] = new Vector<Integer>();
// Adding edges to List
addEdge(adj, 1, 2);
addEdge(adj, 3, 2);
addEdge(adj, 4, 3);
System.out.print(minimumGroups(adj, N));
}
}
// This code is contributed by 29AjayKumar
import sys
# Function to find the height sizeof
# the current component with vertex s
def height(s, adj, visited):
# Visit the current Node
visited[s] = 1
h = 0
# Call DFS recursively to find the
# maximum height of current CC
for child in adj[s]:
# If the node is not visited
# then the height recursively
# for next element
if (visited[child] == 0):
h = max(h, 1 + height(child, adj,
visited))
return h
# Function to find the minimum Groups
def minimumGroups(adj, N):
# Initialise with visited array
visited = [0 for i in range(N + 1)]
# To find the minimum groups
groups = -sys.maxsize
# Traverse all the non visited Node
# and calculate the height of the
# tree with current node as a head
for i in range(1, N + 1):
# If the current is not visited
# therefore, we get another CC
if (visited[i] == 0):
comHeight = height(i, adj, visited)
groups = max(groups, comHeight)
# Return the minimum bipartite matching
return groups
# Function that adds the current edges
# in the given graph
def addEdge(adj, u, v):
adj[u].append(v)
adj[v].append(u)
# Driver code
if __name__=="__main__":
N = 5
# Adjacency List
adj = [[] for i in range(N + 1)]
# Adding edges to List
addEdge(adj, 1, 2)
addEdge(adj, 3, 2)
addEdge(adj, 4, 3)
print(minimumGroups(adj, N))
# This code is contributed by rutvik_56
using System;
using System.Collections.Generic;
class GFG{
// Function to find the height sizeof
// the current component with vertex s
static int height(int s, List<int> []adj,
int []visited)
{
// Visit the current Node
visited[s] = 1;
int h = 0;
// Call DFS recursively to find the
// maximum height of current CC
foreach (int child in adj[s]) {
// If the node is not visited
// then the height recursively
// for next element
if (visited[child] == 0) {
h = Math.Max(h, 1 + height(child, adj,
visited));
}
}
return h;
}
// Function to find the minimum Groups
static int minimumGroups(List<int> []adj, int N)
{
// Initialise with visited array
int []visited= new int[N + 1];
// To find the minimum groups
int groups = int.MinValue;
// Traverse all the non visited Node
// and calculate the height of the
// tree with current node as a head
for (int i = 1; i <= N; i++) {
// If the current is not visited
// therefore, we get another CC
if (visited[i] == 0) {
int comHeight;
comHeight = height(i, adj, visited);
groups = Math.Max(groups, comHeight);
}
}
// Return the minimum bipartite matching
return groups;
}
// Function that adds the current edges
// in the given graph
static void addEdge(List<int> []adj, int u, int v)
{
adj[u].Add(v);
adj[v].Add(u);
}
// Drivers Code
public static void Main(String[] args)
{
int N = 5;
// Adjacency List
List<int> []adj = new List<int>[N + 1];
for (int i = 0 ; i < N + 1; i++)
adj[i] = new List<int>();
// Adding edges to List
addEdge(adj, 1, 2);
addEdge(adj, 3, 2);
addEdge(adj, 4, 3);
Console.Write(minimumGroups(adj, N));
}
}
// This code is contributed by Rajput-Ji
<script>
// Function to find the height sizeof
// the current component with vertex s
function height(s, adj, visited)
{
// Visit the current Node
visited[s] = 1;
var h = 0;
// Call DFS recursively to find the
// maximum height of current CC
adj[s].forEach(child => {
// If the node is not visited
// then the height recursively
// for next element
if (visited[child] == 0) {
h = Math.max(h, 1 + height(child, adj,
visited));
}
});
return h;
}
// Function to find the minimum Groups
function minimumGroups(adj, N)
{
// Initialise with visited array
var visited = Array(N+1).fill(0);
// To find the minimum groups
var groups = -1000000000;
// Traverse all the non visited Node
// and calculate the height of the
// tree with current node as a head
for (var i = 1; i <= N; i++) {
// If the current is not visited
// therefore, we get another CC
if (visited[i] == 0) {
var comHeight;
comHeight = height(i, adj, visited);
groups = Math.max(groups, comHeight);
}
}
// Return the minimum bipartite matching
return groups;
}
// Function that adds the current edges
// in the given graph
function addEdge(adj, u, v)
{
adj[u].push(v);
adj[v].push(u);
}
// Drivers Code
var N = 5;
// Adjacency List
var adj = Array.from(Array(N+1), ()=>Array())
// Adding edges to List
addEdge(adj, 1, 2);
addEdge(adj, 3, 2);
addEdge(adj, 4, 3);
document.write( minimumGroups(adj, N));
</script>
Output:
3
Time Complexity: O(V+E), where V is the number of vertices and E is the set of edges.
Auxiliary Space: O(V).
