Program to calculate distance between two points

You are given two coordinates (x1, y1) and (x2, y2) of a two-dimensional graph. Find the distance between them.

Examples: 

Input : x1, y1 = (3, 4)
x2, y2 = (7, 7)
Output : 5

Input : x1, y1 = (3, 4)
x2, y2 = (4, 3)
Output : 1.41421

Calculate the distance between two points.

We will use the distance formula derived from Pythagorean theorem. The formula for distance between two point (x1, y1) and (x2, y2) is
Distance = \sqrt{(x2-x1)^{2} + (y2-y1)^{2}}
We can get above formula by simply applying Pythagoras theorem

Below is the implementation of above idea.

#include <bits/stdc++.h>
using namespace std;

// Function to calculate distance
float distance(int x1, int y1, int x2, int y2)
{
    return sqrt(pow(x2 - x1, 2) + pow(y2 - y1, 2) * 1.0);
}

// Drivers Code
int main()
{
    cout << distance(3, 4, 4, 3);
    return 0;
}

#include <math.h>
#include <stdio.h>

// Function to calculate distance
float distance(int x1, int y1, int x2, int y2)
{
    return sqrt(pow(x2 - x1, 2) + pow(y2 - y1, 2) * 1.0);
}

// Drivers Code
int main()
{
    printf("%f", distance(3, 4, 4, 3));
    return 0;
}

// Java code to compute distance

class GFG {
    // Function to calculate distance
    static double distance(int x1, int y1, int x2, int y2)
    {
        return Math.sqrt(Math.pow(x2 - x1, 2)
                         + Math.pow(y2 - y1, 2) * 1.0);
    }
    // Driver code
    public static void main(String[] args)
    {
        System.out.println(
            Math.round(distance(3, 4, 4, 3) * 100000.0)
            / 100000.0);
    }
}

# Python3 program to calculate 
# distance between two points

import math

# Function to calculate distance
def distance(x1 , y1 , x2 , y2):
    return math.sqrt(math.pow(x2 - x1, 2) +
                math.pow(y2 - y1, 2))

# Drivers Code
print("%.6f"%distance(3, 4, 4, 3))

// C# code to compute distance
using System;

class GFG 
{
    // Function to calculate distance
    static double distance(int x1, int y1, int x2, int y2)
    {
        return Math.Sqrt(Math.Pow(x2 - x1, 2) + 
                      Math.Pow(y2 - y1, 2) * 1.0);
    }
    
    // Driver code
    public static void Main ()
    {
        Console.WriteLine(Math.Round(distance(3, 4, 4, 3)
                                   * 100000.0)/100000.0);
    }
}

// Function to calculate distance
function distance(x1, y1, x2, y2) {
    return Math.sqrt(Math.pow(x2 - x1, 2) + Math.pow(y2 - y1, 2));
}

// Driver Code
console.log(distance(3, 4, 4, 3).toFixed(6));

1.41421