Divergence and Curl are differential operators in vector calculus. The divergence is a scalar operator applied to a 3D vector field, while the curl is a vector operator that measures the rotation of the field in three-dimensional space.

Divergence
Divergence is a vector calculus operator that measures the magnitude of a vector field's source or sink at a given point. In other words, it quantifies how much a vector field spreads out (diverges) or converges (compresses) at that point.
For a vector field F = (F1, F2, F3) in three-dimensional space, where F1, F2, and F3 are the components of the vector field, the divergence of F is defined as:
div F = ∇.F = ∂/∂x(F1) + ∂/∂y(F2) + ∂/∂z(F3)
where,
- ∇⋅ is Divergence Operator (Dot Product of Del Operator ∇ with Vector Field F)
Curl
Curl is a vector operator that describes the infinitesimal rotation of a vector field in three-dimensional space. In other words, it measures the tendency of the field to rotate around a point. The curl of a vector field provides information about the rotational motion or the "twisting" of the field lines around a given point.
For a vector field F = (F1, F2, F3) in three-dimensional space, where F1, F2, and F3 are the components of the vector field, the curl of F is defined as:
curl F = ∇×F = (∂F3/∂y - ∂F2/∂z, ∂F1/∂z - ∂F3/∂x, ∂F2/∂x - ∂F1/∂y)
where,
- ∇× is Curl Operator (Cross Product of Del Operator ∇ with Vector Field F)
Divergence of Vector Field
The divergence of a vector field is a scalar field, denoted as "div." To calculate the divergence, you take the scalar product of the vector operator (∇) applied to the vector field, denoted as F(x, y). In two dimensions, for a vector field F(x, y), the divergence is given by:
In three dimensions, for a vector field F(x, y, z) represented as
Divergence helps understand how a vector field's behavior changes concerning a point, providing valuable insights into the field's sources and sinks.
Curl of a Vector Field
The curl of a vector field is another vector field. To find the curl, we perform the vector product of the del operator applied to the vector field
This can also be expressed as,
In simpler terms, the curl of a vector field indicates how the field rotates or circulates at each point in space.
Divergence of Curl
In a smooth vector field
Proof of Divergence of Curl
Vector Field
Curl of
Use Cross-Product Identities
Apply Clairaut's Theorem
Since mixed partial derivatives are equal
The result simplifies to
Equations of Divergence and Curl
Curl Equation: The curl of a vector field
Divergence Equation: The divergence of a vector field
Divergence of Curl: The divergence of the curl of a vector field
Curl of a Gradient: The curl of the gradient of a scalar function (f) is the zero vector, i.e.
These equations play a crucial role in vector calculus, describing the rotation and flow properties of vector fields, as well as the relationships between divergence and curl.
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Solved Examples on Divergence and Curl
Example 1: Consider the vector field
Solution:
Given,
- Vector Field
\vec{F} = 3xy\hat{i} + 2z\hat{j} - x^2\hat{k} For Divergence,
\nabla \cdot \vec{F} = \frac{\partial}{\partial x}(3xy) + \frac{\partial}{\partial y}(2z) + \frac{\partial}{\partial z}(-x^2) = 3y + 0 - 2x
So, the divergence of
\vec{F} is ( 3y - 2x )To determine if it's a source or sink, we need additional information about the region and boundary conditions.
- If
\nabla \cdot \vec{F}~>~0 in a region, it's a source- If
\nabla \cdot \vec{F}~<~0 , it's a sink
Example 2: Given the vector field
Solution:
For Vector Field:
\vec{G}~=~(2y - z)\hat{i} + (x + z)\hat{j} + (y - x)\hat{k} ,For Curl:
\nabla \times \vec{G}~=~\begin{vmatrix} \hat{i} & \hat{j} & \hat{k} \\ \frac{\partial}{\partial x} & \frac{\partial}{\partial y} & \frac{\partial}{\partial z} \\ 2y - z & x + z & y - x \end{vmatrix} ⇒
\left(\frac{\partial}{\partial y}(y - x) - \frac{\partial}{\partial z}(x + z)\right)\hat{i} - \left(\frac{\partial}{\partial x}(2y - z) - \frac{\partial}{\partial z}(y - x)\right)\hat{j} + \left(\frac{\partial}{\partial x}(x + z) - \frac{\partial}{\partial y}(2y - z)\right)\hat{k} ⇒
(1 + 1)\hat{i} - (-2 + 1)\hat{j} + (1 - 2)\hat{k} ⇒
2\hat{i} + \hat{j} - \hat{k} So, curl of
\vec{G} is2\hat{i} + \hat{j} - \hat{k}
Practice Questions of Divergence and Curl
Q1. Given the vector field
Q2. For the vector field
Q3. Consider the vector field
Q4. Given the vector field
Q5. For a vector field