The function f(x) limit as x approaches a particular value a is written as lim(x→a) f(x). It stands for the value that f(x) gets when x is near a, but not necessarily equal to f(a).

Limits at Infinity
The limit at infinity is the limit that describes the behavior of the function as x approaches plus or minus infinity.
- The limits are limits that are the ones that demonstrate the asymptotic behavior of the function, which are the values that f(x) is getting close to as x becomes very large or very small.
- The formal definition of limits at infinity states that lim(x→∞) f(x) = L if for every ε > 0, there exists a real number M such that |f(x) - L| < ε for all x > M. Similarly, lim(x→-∞) f(x) = L if for every ε > 0, there exists a real number M such that |f(x) - L| < ε for all x < -M.
Properties of Limits at Infinity
The properties of limit at infinity are mentioned below:
Constant Rule: If f(x) = c, where c is a constant, then lim(x→∞) f(x) = c and lim(x→-∞) f(x) = c.
Power Rule: If f(x) = xn, where n is a positive integer, then:
- If n is even, lim(x→∞) f(x) = ∞ and lim(x→-∞) f(x) = ∞.
- If n is odd, lim(x→∞) f(x) = ∞ and lim(x→-∞) f(x) = -∞.
Reciprocal Rule: If f(x) = 1/x, then lim(x→∞) f(x) = 0 and lim(x→-∞) f(x) = 0.
Sum Rule: If lim(x→∞) f(x) = L1 and lim(x→∞) g(x) = L2, then lim(x→∞) [f(x) + g(x)] = L1 + L2.
Difference Rule: If lim(x→∞) f(x) = L1 and lim(x→∞) g(x) = L2, then lim(x→∞) [f(x) - g(x)] = L1 - L2.
Product Rule: If lim(x→∞) f(x) = L1 and lim(x→∞) g(x) = L2, then lim(x→∞) [f(x) * g(x)] = L1 * L2.
Quotient Rule: If lim(x→∞) f(x) = L1 and lim(x→∞) g(x) = L2 ≠ 0, then lim(x→∞) [f(x) / g(x)] = L1 / L2.
Evaluating Limits at Infinity
To determine the limits at infinity, we can utilize several methods, for instance, direct substitution, factoring, rationalizing the numerator or the denominator, and the properties of limits. Let's consider an example:
Example: Evaluate lim(x→∞) (x2 + 3x) / (2x2 - 5).
Solution:
Divide the numerator and denominator by the highest power of x in the denominator, which is x2.
(x2 + 3x) / (2x2 - 5) = (1 + 3/x) / (2 - 5/x2)
As x approaches infinity, 3/x approaches 0 and 5/x2 approaches 0.
Therefore, lim(x→∞) (x2 + 3x) / (2x2 - 5) = lim(x→∞) (1 + 3/x) / (2 - 5/x2) = 1/2.
Calculus of Limits at Infinity
Limits at infinity are the main point in calculus, especially in the area of asymptotic behavior, continuity, and differentiability of functions. They are employed to study the mode of functions as they come to close or far from infinity and to check the presence of horizontal asymptotes.
Limits of Rational Functions at Infinity
The limit of a rational function f(x) = P(x) / Q(x) as x approaches infinity depends on the degrees of the polynomials P(x) and Q(x). If deg(P(x)) < deg(Q(x)), then lim(x→∞) f(x) = 0. If deg(P(x)) > deg(Q(x)), then lim(x→∞) f(x) = ∞. If deg(P(x)) = deg(Q(x)), then lim(x→∞) f(x) = a, where a is the ratio of the leading coefficients of P(x) and Q(x).
For example, consider the rational function f(x) = (x2 + 3x + 1) / (2x2 - 5). Here, deg(P(x)) = 2 and deg(Q(x)) = 2, so lim(x→∞) f(x) = 1/2.
Limits of Trigonometric Functions at Infinity
The limits of the trigonometric functions when x goes to infinity are determined by the type of function and its periodicity. To illustrate this, lim(x→∞) sin(x) and lim(x→∞) cos(x) do not exist because the functions oscillate between -1 and 1 without getting closer to any specific value. On the other hand, lim(x→∞) sin(x) / x = 0 and lim(x→∞) cos(x) / x = 0.
Limits of Exponential and Logarithmic Functions at Infinity
Exponential functions of the form f(x) = ax, where a > 0, have the following limits:
- If a > 1, then lim(x→∞) f(x) = ∞ and lim(x→-∞) f(x) = 0.
- If 0 < a < 1, then lim(x→∞) f(x) = 0 and lim(x→-∞) f(x) = ∞.
Logarithmic functions of the form f(x) = loga(x), where a > 0 and a ≠ 1, have the following limits:
If x approaches ∞, then f(x) approaches ∞.
If x approaches 0+ (positive values), then f(x) approaches -∞.
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Solved Examples in Limits at infinity
Example 1: Evaluate the limit as x approaches infinity for the function ?(?) = 2x3−5x2+3
Solution:
As x approaches infinity, the term with the highest power of x dominates the function. Therefore, the limit is:
lim?→∞(2x3−5x2+3) = ∞
Example 2: Find the limit as x approaches infinity for the function ?(?)=4x2+2 / x3−3
Solution:
Divide the numerator and denominator by the highest power of x to simplify the expression:
lim?→∞4x2+2x3−3 = lim?→∞ 4/x +2/x2 / 1−3/x3
As x approaches infinity, the terms with 1/? and 1/?2 approach 0, leading to:
lim?→∞ 4x2+2x3−3 = 0+0 / 1−0 = 0
Practice Questions on Limits at Infinity
Q1. Evaluate the limit as x approaches infinity for the function f(x) = 3x2 − 2x + 5
Q2. Compute the limit as x approaches infinity for the function f(x) = 5x2+3x−12/x3+7
Q3. Calculate the limit as x tends to infinity for the function f(x) = e-x
Q4. Evaluate the limit as x tends to negative infinity for the function f(x) = e2x -x2