Logarithm Formulas

Last Updated : 14 Apr, 2026

A logarithm is a mathematical concept that provides an alternative way of expressing exponents.

  • It represents the power to which a given base must be raised to obtain a specific number.
  • It is especially useful when dealing with exponential relationships, as it simplifies complex calculations and makes them easier to handle.
log_2

The properties of logarithms are a set of rules that help simplify and solve logarithmic expressions by applying the laws of exponents and are given below.

properties_of_logarithms

Other Logarithm Formulas

Various other Logarithm Formulas are:

  • \log_b\left(n^{\frac{1}{a}}\right) = \frac{1}{a}\,\log_b(n)
  • log of 1 = loga1 = 0
  • logaa = 1 (Identity rule)
  • logba= logbc =>  a= c (Equality rule)
  • a^{log_ax} = x (Raised to log)

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Solved Examples

Example 1: Solve log2(x) = 4
Solution:

log2(x) = 4
24 = x
x = 16

Example 2: Solve log2(8) = x
Solution:

log2(8) = x

⇒ 2x = 8
⇒ 2x = 23
⇒ x = 3

Example 3: Find the value of x if log6(x - 3) = 1.
Solution:

log6(x - 3) = 1

⇒ 61 = (x - 3)
⇒ x - 3 = 6
⇒ x = 9

Example 4: Find  x if log(x - 2) + log(x + 2) = log21
Solution: 

log(x - 2) + log(x + 2) = log21  

⇒ log(x - 2) + log(x + 2) = 0 [log(1) =0]
⇒ log[(x - 2)(x + 2)] = 0 [Product Rule]
⇒ (x - 2)(x + 2) = 1 [Antilog(0) = 1]
⇒ x2 - 4 = 1
⇒ x2 = 5
⇒ x = ±√5 [Log of Negative Number is Not Defined]
⇒ x = √5

Example 5: Find the value of log9(59049).
Solution:

Given log9 (59049) [95= 59049]

= log9(9)5
= 5.log9(9) (identity rule i.e logaa]
= 5

Example 6: Express log10(5) + 1 in form of log10x
Solution:

Given log10(5) + 1

= log10(5) + log1010 [Identity Rule]
= log10(5 × 10) [Product Rule]
= log1050

Example 7: Find the value of x if log10(x2 - 15) = 1.
Solution:

log10(x2 - 15) = 1
log10(x2 - 15) = log1010 [Identity Rule]

Applying Antilog,

⇒ (x2 - 15) = 10
⇒ x2 = 25
⇒ x = ±5

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