Parallelogram

Last Updated : 27 Feb, 2026

A parallelogram is a two-dimensional geometrical shape whose opposite sides are equal in length and are parallel. The opposite angles of a parallelogram are equal in measure, and the sum of adjacent angles of a parallelogram is equal to 180 degrees.

parallelogram

A parallelogram is a four-sided polygon (quadrilateral), and it has the following key properties:

  1. Opposite Sides are Parallel and Equal: The two pairs of opposite sides are both parallel and have equal lengths, i.e., AB = CD and BC = AD.
  2. Opposite Angles Are Congruent: Opposite angles are equal, meaning ∠A = ∠C and ∠B = ∠D.
  3. Right Angles Form a Rectangle: If one angle is 90°, all angles will be 90°, making it a rectangle.
  4. Diagonals Bisect Each Other: The diagonals cut each other into two equal halves.
  5. Consecutive angles are Supplementary: Any two consecutive angles add up to 180°, i.e., ∠A + ∠B = 180 °.

Types of Parallelogram

There are mainly four types of parallelograms, based on their properties.

Rectangle

A rectangle is a parallelogram with two pairs of equal and parallel opposite sides, along with four right angles.

rectangle

Observe the rectangle ABCD and associate it with the following properties.

  1. Two pairs of parallel sides. Here AB || DC and AD || BC
  2. Four right angles: ∠A = ∠B = ∠C = ∠D = 90°.
  3. The opposite sides are the same length, where AB = DC and AD = BC.
  4. Two equal diagonals where AC = BD.
  5. Diagonals that bisect each other.

Square

A square is a parallelogram with four equal sides and four equal angles.

square

Observe the square ACDB and associate it with the following properties:

  1. Four equal sides are AB = BC = CD = DA.
  2. Right angles are ∠A = ∠B = ∠C = ∠D = 90°.
  3. There are two pairs of parallel sides. Here AB || DC and AD || BC.
  4. Two identical diagonals where AD = BC.
  5. Diagonals are perpendicular and bisect each other; AD is perpendicular to BC.

Rhombus

A parallelogram with four equal sides and equal opposite angles is called a rhombus. Consider the diamond ABCD and assign it the following attributes:

rhombus
  1. In the given figure, the four equal sides are AB = CD = BC = AD. 
  2. The two pairs of parallel sides are AB and || CD and BC and || AD. 
  3. The equal opposite angles are ∠A = ∠B and ∠C = ∠D. 
  4. Here, the diagonals (AC and BD) are perpendicular to each other and bisect at right angles.

Rhomboid

A rhomboid is a quadrilateral with opposite sides that are parallel and equal in length, but the angles are not necessarily right angles. Consider the rhomboid ABCD with the following attributes:

rhomboid
  • The equal opposite sides are AB = CD and BC = AD.
  • The two pairs of parallel sides are AB ∥ CD and BC ∥ AD.
  • The opposite angles are equal: ∠A = ∠C and ∠B = ∠D.
  • The diagonals (AC and BD) bisect each other but are not perpendicular.

Parallelogram Formulas

Area of Parallelogram

The area of ​​a parallelogram is the space covered between its four sides. It can be calculated by knowing the length of the base and the height of the parallelogram and measuring it in square units such as cm or m2.

Consider a parallelogram ABCD with a base (b) and a height (h).
Then, the area of ​​a parallelogram is calculated by the formula:

Area of Parallelogram = base (b) × height (h)

Area of Parallelogram without Height

When the height of the parallelogram is not known, the area can still be found, provided the angle is known to us.

The formula for the area of a parallelogram without height is given as

Parallelogram area = ab Sinθ

where a and b are the sides of the parallelogram and θ is the angle between them.

The perimeter of a parallelogram

The perimeter of a parallelogram is the length of its boundary, so it is equal to the sum of all sides.

In a parallelogram, the opposite sides are equal. Let's say the sides are a and b. Then, the perimeter (P) of the parallelogram with edges is in units of P = 2 (a + b).

Perimeter of Parallelogram = 2 (a + b)

Parallelogram Theorem

Theorem: Parallelograms on the same base and between the same parallels are equal in area.

parallelogram_theorem

To Prove: Area of parallelogram ABCD = Area of parallelogram ABEF

Proof: Let's assume two parallelograms ABCD and ABEF with the same base DC and between the same parallel lines AB and FC

In the figure given below, the two parallelograms, ABCD and ABEF, lie between the same parallel lines and have the same base. Area ABDE is common between them.

Taking a closer look at the two triangles, △BCD and △AEF might be congruent. 

BC = AE (Opposite sides of a parallelogram), 

∠BCD = ∠AEF (These are corresponding angles because BC || AE and CE are the transversal).

∠BDC = ∠AFE (These are corresponding angles because BD || AF and FD are the transversals).

Thus, by the ASA criterion of congruent triangles. These two triangles are congruent, and they must have equal areas. 

area(BCD) = area(AEF)

area(BCD) + area(ABDE) = area(AEF) + area(ABDE) 

area(ABCD) = area(ABEF) 

Hence, parallelograms lying between the same parallel lines and having a common base have equal areas. 

Real-life examples of a Parallelogram

Various examples of parallelograms as observed in our daily life include:

  • We come across various things in our daily life that resemble a parallelogram, such as a computer screen, books, buildings, and tiles, all of which are considered to be in a parallelogram shape.
  • The parallelogram is the most common shape that we encounter daily.
  • Rectangles and squares both can be considered parallelograms and are easily seen in our daily lives.

Solved Examples on Parallelogram

Example 1: Find the length of the other side of a parallelogram with a base of 12 cm and a perimeter of 60 cm.

Given perimeter of a parallelogram = 60cm.
Base length of given parallelogram = 12 cm. 
P = 2 (a + b) units 

Where b = 12cm and P = 40cm.
60 = 2 (a + 12)
60 = 2a + 24
2a = 60 - 24
2a = 36
a = 18cm

Therefore, the length of the other side of the parallelogram is 18 cm. 

Example 2: Find the perimeter of a parallelogram with the base and side lengths of 15 cm and 5 cm, respectively.

Base length of given parallelogram = 15 cm
Side length of given parallelogram = 5 cm

Perimeter of a parallelogram is given by,
P = 2(a + b) units.

Putting the values, we get
P = 2(15 + 5)
P = 2(20)
P = 40 cm

Therefore, the perimeter of a parallelogram will be 40 cm.

Example 3: The angle between two sides of a parallelogram is 90°. If the lengths of two parallel sides are 5 cm and 4 cm, respectively, find the area.

Parallelogram-8

If one angle of the parallelogram is 90°. Then, the rest of the angles are also 90°. Therefore, the parallelogram becomes a rectangle. The area of the rectangle is length times breadth.
Area of parallelogram = 5 × 4
Area of parallelogram = 20cm2

Example 4: Find the area of a parallelogram when the diagonals are given as 8 cm and 10 cm, and the angle between the diagonals is 60°.

In order to find the area of the parallelogram, the base and height should be known, let's first find the base of the parallelogram, applying the law of cosines,

b2 = 42 + 52 - 2(5)(4)cos(120°)
b2 = 16 + 25 - 40(0.8)
b2 = 9
b = 3cm 

Finding the height of the parallelogram,

Parallelogram


4/sinθ = b/sin120
4/sinθ = 3/-0.58
sinθ = -0.773
θ = 50°

Now, to find the height,

Sinθ = h/10
0.76 = h/10
h = 7.6cm

Area of the parallelogram = 1/2 × 3 × 7.6 = 11.4 cm2

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