Quadratic Inequalities

Last Updated : 1 Jun, 2026

A quadratic inequality is an inequality that involves a quadratic expression of the form ax² + bx + c (where a ≠ 0) and compares it with zero, a constant, or another expression using symbols like >, <, ≥, or ≤. It represents the set of values of x for which the inequality is true.

Example

  • x² − 4x + 3 ≥ 0
  • 2x² + x − 5 < 0
  • x² − 9 > 0

Types of Quadratic Inequalities

Quadratic inequalities can be expressed in the following standard forms:

  • ax2 + bx + c > 0 (The quadratic expression is positive.)
  • ax2 + bx + c < 0 (The quadratic expression is negative)
  • ax2 + bx + c ≥ 0 (The quadratic expression is non-negative)
  • ax2 + bx + c ≤ 0 (The quadratic expression is non-positive.)

Steps to solve a Quadratic Inequality

A quadratic inequality can be solved using either factorization or the quadratic formula.

Steps:

Step 1. Write in standard form
Bring the inequality to the form:
ax² + bx + c > 0, < 0, ≥ 0, or ≤ 0

Step 2. Find the roots
Solve ax² + bx + c = 0

  • Factorise if possible, or
  • Use the quadratic formula

Step 3. Mark critical points
Plot the roots on a number line. These points divide the number line into intervals.

Step 4. Test intervals
Pick a value from each interval and substitute into the inequality to check if it satisfies the condition.

Step 5. Write the solution
Select the intervals where the inequality is true and express the answer in inequality or interval notation.

Methods to Solve Quadratic Inequalities

Solving quadratic inequalities means finding the value of x for which it satisfies the given inequality. We can solve a quadratic inequality using two main methods:

Quadratic-Equation-2

Graphical Method

In the graphical method, we first draw the graph of the inequality and then find the solution of the given inequality using the graph. Let's see how to solve quadratic inequalities using the graphical method with the help of an example.

Example: x2 - 3x - 4 > 0

Solution:

We can solve the above example using graphical methods

Step 1: Plotting the graph of the quadratic function y = x2 - 3x - 4

Finding the x-intercepts:
Given quadratic function: y = x2 - 3x - 4

To find the roots, solve for y = 0:
x2 - 3x - 4 = 0

Factorizing the equation or using the quadratic formula:
x2 - 4x + x - 4 = 0
x(x - 4) + 1(x - 4) = 0
(x - 4)(x + 1) = 0
Therefore, the roots are x = 4 and x = -1

Plotting the graph:

Quadratic-Equation

Step 2: Identifying regions where the graph lies above the x-axis (where y > 0)

We are looking for the regions where the quadratic function is positivee(y > 0).
The function is y = x2 - 3x - 4. We know the roots are x = 4 and x = -1.

Step 3: Determining the x-values within these regions to obtain the solution set

Based on the graph, the regions where y > 0 are:
- x < -1
- x > 4

Therefore, the solution set for x2 - 3x - 4 > 0 is x < -1 or x > 4.

This solution is derived from observing the parts of the graph where the quadratic function y = x2 - 3x - 4 is above the x-axis. 

Algebraic Method

Algebraically, we can solve a quadratic inequality using the following three methods:

1. Factoring

In factoring, we split the given quadratic expression into the product of its factors to find out the solution.

Example: Find out the solution for the inequality x2 - 3x - 4 > 0 using the factoring method.

Solution:

Given inequality: x2 - 3x - 4 > 0

Step 1: Factor the quadratic expression:
(x - 4)(x + 1) > 0

Step 2: Identify intervals based on the factors:
Interval I: x < -1

For x < -1, consider the factors (x - 4)(x + 1):

Pick a test point within the interval, say x = -2, substitute into (x - 4)(x + 1):
((-2) - 4)((-2) + 1) = (-6)(-1) = 6 > 0

The inequality holds for x < -1.
Interval II: -1 < x < 4

For -1 < x < 4, consider the factors (x - 4)(x + 1):

Pick a test point within the interval, say x = 0, substitute into (x - 4)(x + 1):
(0 - 4)(0 + 1) = (-4)(1) = -4 < 0

The inequality doesn't hold for -1 < x < 4.
Interval III: x > 4

For x > 4, consider the factors (x - 4)(x + 1):

Pick a test point within the interval, say x = 5, substitute into (x - 4)(x + 1):
(5 - 4)(5 + 1) = (1)(6) = 6 > 0

The inequality holds for x > 4.

Therefore, the solution is x < -1 or x > 4.

Quadratic Formula

Use the quadratic formula to find the roots and determine the intervals where the expression is positive.

Example: Find the solution of the given inequality x2 - 3x - 4 > 0 using the quadratic formula.

Solution:

Step 1: Apply the quadratic formula to find the roots:

x = [3 ± √((-3)2 - 4×1×(-4))]/(2×1)
x = [3 ± √(25)]/2
x = [3 ± 5]/2

Roots: x = 4 or x = -1

Step 2: Test intervals to determine where the expression is positive:

Interval I: x < -1 → (x2 - 3x - 4) > 0
For x < -1, consider the quadratic expression (x2 - 3x - 4):

Choose a test point, say x = -2, substitute into (x2 - 3x - 4):
((-2)2 - 3(-2) - 4) = (4 + 6 - 4) = 6 > 0

The inequality holds for x < -1.
Interval II: -1 < x < 4 → (x2 - 3x - 4) < 0

For -1 < x < 4, consider the quadratic expression (x2 - 3x - 4):

Choose a test point, say x = 0, substitute into (x2 - 3x - 4):
((0)2 - 3(0) - 4) = (-4) < 0

The inequality doesn't hold for -1 < x < 4.
Interval III: x > 4 → (x2 - 3x - 4) > 0

For x > 4, consider the quadratic expression (x2 - 3x - 4):

Choose a test point, say x = 5, substitute into (x2 - 3x - 4):
((5)2 - 3(5) - 4) = (25 - 15 - 4) = 6 > 0

The inequality holds for x > 4.

Therefore, the solution is x < -1 or x > 4.

Completing the Square

In completing the square method, convert the quadratic expression into a perfect square trinomial to solve the inequality.

Example: Solve the given inequality x2 - 3x - 4 > 0 by using Completing the Square Method

Solution:

Step 1: Complete the square:

x2 - 3x - 4 = (x - (3/2))2 - 25/4

Step 2: Set up the inequality:

(x - (3/2))2 - 25/4 > 0

Step 3: Find the intervals where the inequality holds:

This gives two cases:

Case 1: x - (3/2) > 5/2
x > 8/2
x > 4

Case 2: x - (3/2) < -5/2
x < -2/2
x < -1

Therefore, the solution is x < -1 or x > 4.

Solved Examples

Example 1. Solve the inequality: x2 - 4x + 3 > 0.

Solution:

Given inequality: x2 - 4x + 3 > 0

Step 1: Factorize the quadratic expression:
x2 - 4x + 3 = (x - 3)(x - 1) > 0

Step 2: Find intervals where the expression is positive:
Interval I: x < 1

For x < 1, consider the factors (x - 3)(x - 1):

Pick a test point, say x = 0, substitute into (x - 3)(x - 1):
(0 - 3)(0 - 1) = (-3)(-1) = 3 > 0

The inequality holds for x < 1.
Interval II: 1 < x < 3

For 1 < x < 3, consider the factors (x - 3)(x - 1):

Pick a test point, say x = 2, substitute into (x - 3)(x - 1):
(2 - 3)(2 - 1) = (-1)(1) = -1 < 0

The inequality doesn't hold for 1 < x < 3.
Interval III: x > 3

For x > 3, consider the factors (x - 3)(x - 1):

Pick a test point, say x = 4, substitute into (x - 3)(x - 1):
(4 - 3)(4 - 1) = (1)(3) = 3 > 0

The inequality holds for x > 3.

Therefore, the solution is x < 1 or x > 3.

Example 2. Solve the inequality: x2 + 2x - 15 ≤ 0.

Solution:

Given inequality: x2 + 2x - 15 ≤ 0

Step 1: Factorize the quadratic expression:
x2 + 2x - 15 = (x + 5)(x - 3) ≤ 0

Step 2: Find intervals where the expression is non-positive:
Interval I: -5 ≤ x ≤ 3

For -5 ≤ x ≤ 3, consider the factors (x + 5)(x - 3):

Pick a test point within the interval, say x = 0, substitute into (x + 5)(x - 3):
(0 + 5)(0 - 3) = (5)(-3) = -15 ≤ 0

The inequality holds for -5 ≤ x ≤ 3.

Therefore, the solution is -5 ≤ x ≤ 3.

Example 3. Solve the inequality: 2x2 - 5x + 2 > 0.

Solution:

Given inequality: 2x2 - 5x + 2 > 0

Step 1: Factorize the quadratic expression:
2x2 - 5x + 2 = (2x - 1)(x - 2) > 0

Step 2: Find intervals where the expression is positive:
Interval I: x < 1/2
For x < 1/2, consider the factors (2x - 1)(x - 2):

Pick a test point within the interval, say x = 0, substitute into (2x - 1)(x - 2):
(2 × 0 - 1)(0 - 2) = (-1)(-2) = 2 > 0

The inequality holds for x < 1/2.
Interval II: x > 2

For x > 2, consider the factors (2x - 1)(x - 2):

Pick a test point within the interval, say x = 3, substitute into (2x - 1)(x - 2):
(2 × 3 - 1)(3 - 2) = (5)(1) = 5 > 0

The inequality holds for x > 2.

Therefore, the solution is x < 1/2 or x > 2.

Example 4. Solve the inequality: 3x2 - 4x - 4 ≤ 0.

Solution:

Given inequality: 3x2 - 4x - 4 ≤ 0

Step 1: Factorize the quadratic expression:
3x2 - 4x - 4 = (3x + 2)(x - 2) ≤ 0

Step 2: Find intervals where the expression is non-positive:
Interval I: -2/3 ≤ x ≤ 2
For -2/3 ≤ x ≤ 2, consider the factors (3x + 2)(x - 2):

Pick a test point within the interval, say x = 0, substitute into (3x + 2)(x - 2):
(3 × 0 + 2)(0 - 2) = (2)(-2) = -4 ≤ 0
The inequality holds for -2/3 ≤ x ≤ 2.

Therefore, the solution is -2/3 ≤ x ≤ 2.

Example 5. Solve the inequality: x2 + 6x + 9 > 0

Solution:

Given inequality: x2 + 6x + 9 > 0

Step 1: Factorize the quadratic expression:
x2 + 6x + 9 = (x + 3)(x + 3) > 0

Step 2: Find intervals where the expression is positive:
Interval I: x > -3

For x > -3, consider the factor (x + 3)^2:
For any value of x greater than -3, (x + 3)^2 will always be greater than zero because it represents a square value.

Therefore, the solution is x > -3.

Practice Questions

Question 1. Solve the inequality: 2x2 - 7x + 3 < 0.

Question 2. Solve the inequality: x2 + 4x + 4 ≥ 0.

Question 3. Solve the inequality: 4x2 - 12x - 3 > 0.

Question 4. Solve the inequality: 5x2 - 8x + 3 ≤ 0.

Question 5. Solve the inequality: 3x2 + 5x - 2 > 0.

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