Re: [RFC brainstorm] Approximately equals operator
I love April Fools jokes.
Yes, and let's add the null coalescing increment and decrement operators:
$foo??++ and $bar??-- . I want to ensure that an undeclared or null
variable defaults to 0 before becoming 1 or -1 without needing to manually
instantiate the variable as 0.
Pfft.
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Anyhow, why wouldn't rounding precision be decided by the precision of the
float/integer with the lesser precision?
1. 1.55 ~= 1.5499 // true (because rounding 1.5499 to 2 decimal places is
1.55)
2. 3.1415 ~= 3.141 // false (because rounding 3.1415 to three decimal
places is 3.142)
3. 1000 ~= 999.50000001 // true (rounding to integer comparison)
mickmackusa
Thread (17 messages)