Re: Re: $arr = array('Hello', 'world'); $arr();

From: Date: Wed, 08 Jun 2011 13:48:34 +0000
Subject: Re: Re: $arr = array('Hello', 'world'); $arr();
References: 1 2 3 4 5  Groups: php.internals 
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On Wed, 8 Jun 2011 15:39:59 +0200, Jordi Boggiano wrote:
On Wed, Jun 8, 2011 at 2:46 PM, Felipe Pena <[email protected]> wrote:
class foo {   public function __construct() {
     $this->bar = function () { return 1; };
     // $this->bar(); // error
     $x = $this->bar;
     $x(); // ok
     $this->bar = array($this, 'baz');
     // $this->bar(); // error
     $x = $this->bar;
     $x(); // ok
  }   public function baz() {
     echo 'baz';
   } }
What he meant was passing an existing method as a callback if you don't invoke it, i.e. passing "$this->bar" instead of array($this, "bar"). I don't know how hard it'd be to achieve, but it sounds pretty awesome to me. Cheers
Yep, just what I meant.

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